A=(2x+3)^2+(2x+3)(2x-3)-(2x-3)^2

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Solution for A=(2x+3)^2+(2x+3)(2x-3)-(2x-3)^2 equation: 



=(2A+3)^2+(2A+3)(2A-3)-(2A-3)^2

We move all terms to the left:

-((2A+3)^2+(2A+3)(2A-3)-(2A-3)^2)=0

We use the square of the difference formula

4A^2+9=0

a = 4; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·4·9
Δ = -144
Delta is less than zero, so there is no solution for the equation

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